From Peak Voltage:
$$ V_{pp} = 2 \cdot V_p $$
From RMS Voltage:
$$ V_{pp} = 2\sqrt{2} \cdot V_{rms} \approx 2.828 \cdot V_{rms} $$
From Average Voltage:
$$ V_{pp} = \pi \cdot V_{avg} \approx 3.142 \cdot V_{avg} $$
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